Flatten a Higher Order Observable with concatAll in RxJS

André Staltz
InstructorAndré Staltz
Share this video with your friends

Social Share Links

Send Tweet
Published 8 years ago
Updated 5 years ago

Besides switch and mergeAll, RxJS also provides concatAll as a flattening operator. In this lesson we will see how concatAll handles concurrent inner Observables and how it is just mergeAll(1).

egghead
egghead
~ 40 seconds ago

Member comments are a way for members to communicate, interact, and ask questions about a lesson.

The instructor or someone from the community might respond to your question Here are a few basic guidelines to commenting on egghead.io

Be on-Topic

Comments are for discussing a lesson. If you're having a general issue with the website functionality, please contact us at support@egghead.io.

Avoid meta-discussion

  • This was great!
  • This was horrible!
  • I didn't like this because it didn't match my skill level.
  • +1 It will likely be deleted as spam.

Code Problems?

Should be accompanied by code! Codesandbox or Stackblitz provide a way to share code and discuss it in context

Details and Context

Vague question? Vague answer. Any details and context you can provide will lure more interesting answers!

Markdown supported.
Become a member to join the discussionEnroll Today