Specify this using .call() or .apply()
this argument is usually set implicitly, depending on how the function is called. Ordinary function calls, method calls, and constructor calls all lead to a different
We can also call a function with an explicit
this argument using
Function.prototype.apply(). Both methods accept a
thisArg as their first parameter and a variable number of additional arguments.
This lesson shows how to use
apply() and explains how they differ.